4x^2+9x+5=5

Solution for 4x^2+9x+5=5 equation:

4x^2+9x+5=5

We move all terms to the left:

4x^2+9x+5-(5)=0

We add all the numbers together, and all the variables

4x^2+9x=0

a = 4; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·4·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*4}=\frac{-18}{8}
=-2+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*4}=\frac{0}{8}
=0
$